Pblock Elementsii Result Question 12
12. The shape of $\mathrm{XeO} _2 \mathrm{~F} _2$ molecule is
(2012)
(a) trigonal bipyramidal
(b) square planar
(c) tetrahedral
(d) see-saw
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Answer:
Correct Answer: 12. ( a )
Solution:
$\text { In } \mathrm XeO _2 \mathrm F _2 \text {, the bonding arrangement around the central atom } \mathrm{Xe} \text { is }$
$4 \sigma$ bonds $+1.01 p=5$
Hybridisation of $\mathrm{Xe}=s p^3 d$
$s p^3 d$-hybridisation corresponds to trigonal bipyramidal geometry.
Also, in trigonal bipyramidal geometry, lone pairs remain present on equatorial positions in order to give less electronic repulsion.
NOTE: According to Bent’s rule, the more electronegative atoms must be present on axial position. Hence, $F$ are kept on axial positions
BETA
