Pblock Elementsii Result Question 21
21. $\mathrm{HBr}$ and $\mathrm{HI}$ reduce sulphuric acid, $\mathrm{HCl}$ can reduce $\mathrm{KMnO} _4$ and $\mathrm{HF}$ can reduce
(1981,1 M)
(a) $\mathrm{H} _2 \mathrm{SO} _4$
(b) $\mathrm{KMnO} _4$
(c) $\mathrm{K} _2 \mathrm{Cr} _2 \mathrm{O} _7$
(d) None of these
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Answer:
Correct Answer: 21. ( d )
Solution:
- Fluorine, being the most electronegative, its size is very small. Therefore, it does not have a tendency to loose electrons. Hence, HF does not act as a reducing agent.
BETA
