Pblock Elementsii Result Question 31
Passage
The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other interatomic interactions.
The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers $+2,+4$ and $+6 . \mathrm{XeF}_4$ reacts violently with water to give $\mathrm{XeO}_3$. The compounds of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell.
(2007, $3 \times 4 \mathrm{M}=12 \mathrm{M}$ )
31. The structure of $\mathrm{XeO} _3$ is
(a) linear
(b) planar
(c) pyramidal
(d) T-shaped
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Answer:
Correct Answer: 31. ( c )
Solution:
Xe is $s p^3$-hybridised with one lone pair. Hence, molecule
$\mathrm{XeO}_3$ has pyramidal shape.
BETA
