Pblock Elementsii Result Question 5
5. The type of hybridisation and number of lone pair(s) of electrons of $\mathrm{Xe}$ in $\mathrm{XeOF} _4$, respectively, are
(2019 Main, 10 Jan I)
(a) $s p^3 d^2$ and $1$
(b) $s p^3 d$ and $2$
(c) $s p^3 d$ and $1$
(d) $s p^3 d^2$ and $2$
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Answer:
Correct Answer: 5. ( a )
Solution:
- In $\mathrm{XeOF} _4, \mathrm{Xe}$ is $s p^3 d^2$-hybridised. Geometry of the molecule is octahedral, but shape of the molecule is square pyramidal. According to VSEPR, theory it has one $\pi$ bond. Remaining six electron pairs form an octahedron with one position occupied by a lone pair.
Here, $Xe$ contains one lone pair of electrons.
BETA
