pBlock ElementsII 1 Question 66
61. The unbalanced chemical reactions given in Column I show missing reagent or condition (?) which are provided in Column II. Match Column I with Column II and select the correct answer using the codes given below the Columns.
(2013 Adv.)
| Column I | Column II | |
|---|---|---|
| P. | $\mathrm{PbO} _{2}+\mathrm{H} _{2} \mathrm{SO} _{4} \xrightarrow{?} \mathrm{PbSO} _{4}+\mathrm{O} _{2}+$ other product | 1. $\mathrm{NO}$ |
| Q. | $\mathrm{Na} _{2} \mathrm{S} _{2} \mathrm{O} _{3}+\mathrm{H} _{2} \mathrm{O} \stackrel{?}{\longrightarrow} \mathrm{NaHSO} _{4}+$ other product | 2. $ I _{2}$ |
| R. | $\mathrm{N} _{2} \mathrm{H} _{4} \stackrel{?}{\longrightarrow} \mathrm{N} _{2}+$ other product | 3. Warm |
| S. | $\mathrm{XeF} _{2} \stackrel{?}{\longrightarrow} \mathrm{Xe}+$ other product | 4. $ \mathrm{Cl} _{2}$ |
Codes
| P | Q | R | S | |
|---|---|---|---|---|
| (a) | 4 | 2 | 3 | 1 |
| (b) | 3 | 2 | 1 | 4 |
| (c) | 1 | 4 | 2 | 3 |
| (d) | 3 | 4 | 2 | 1 |
Show Answer
Answer:
Correct Answer: 61. (d)
Solution:
- (P) $2 \mathrm{PbO} _{2}+2 \mathrm{H} _{2} \mathrm{SO} _{4} \xrightarrow{\text { Warm (3) }} 2 \mathrm{PbSO} _{4}+\mathrm{O} _{2}+2 \mathrm{H} _{2} \mathrm{O}$
(Q) $\mathrm{Na} _{2} \mathrm{S} _{2} \mathrm{O} _{3}+\mathrm{H} _{2} \mathrm{O} \xrightarrow{\mathrm{Cl} _{2}(4)} \mathrm{NaHSO} _{4}+\mathrm{HCl}$
(R) $\mathrm{N} _{2} \mathrm{H} _{4} \xrightarrow{\mathrm{I} _{2}(2)} \mathrm{N} _{2}+\mathrm{Hl}$
(S) $\mathrm{XeF} _{2} \xrightarrow{\mathrm{NO}(1)} \mathrm{Xe}+\mathrm{NOF}$
Thus, $\mathrm{P}-(3), \mathrm{Q}-(4)$, $\mathrm{R}-(2)$, $\mathrm{S}-(1)$
BETA
