pBlock ElementsII 1 Question 76
71. Among the following, the number of compounds that can react with $\mathrm{PCl} _{5}$ to give $\mathrm{POCl} _{3}$ is $\mathrm{O} _{2}, \mathrm{CO} _{2}, \mathrm{SO} _{2}, \mathrm{H} _{2} \mathrm{O}$, $\mathrm{H} _{2} \mathrm{SO} _{4}, \mathrm{P} _{4} \mathrm{O} _{10}$.
(2011)
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Answer:
Correct Answer: 71. $(4)$
Solution:
$\mathrm{PCl} _{5}$ produces $\mathrm{POCl} _{3}$ with the following reagents
$\begin{aligned} \mathrm{PCl} _{5}+\mathrm{SO} _{2} & \longrightarrow \mathrm{POCl} _{3}+\mathrm{SOCl} _{2} \\ \mathrm{PCl} _{5}+\mathrm{H} _{2} \mathrm{O} & \longrightarrow \mathrm{POCl} _{3}+2 \mathrm{HCl} \\ 2 \mathrm{PCl} _{5}+\mathrm{H} _{2} \mathrm{SO} _{4} & \longrightarrow \mathrm{SO} _{2} \mathrm{Cl} _{2}+2 \mathrm{POCl} _{3}+2 \mathrm{HCl} \\ 6 \mathrm{PCl} _{5}+\mathrm{P} _{4} \mathrm{O} _{10} & \longrightarrow 10 \mathrm{POCl} _{3} \end{aligned}$
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