Periodic Classification and Periodic Properties 2 Question 31
Assertion and Reason
Read the following questions and answer as per the direction given below :
(a) Statement I is true; Statement II is true; Statement II is the correct explanation of Statement I.
(b) Statement I is true; Statement II is true; Statement II is not the correct explanation of Statement I.
(c) Statement I is true; Statement II is false.
(d) Statement I is false; Statement II is true.
31.
Statement $\mathbf{I} \mathrm{Pb}^{4+}$ compounds are stronger oxidising agents than $\mathrm{Sn}^{4+}$ compounds. Statement II The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to ‘inert pair effect’.
$(2008,3 M)$
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Answer:
Correct Answer: 31. (c)
Solution:
Statement $I$ is true. Stronger oxidising agent is one which itself can easily be reduced. $\mathrm{Pb}^{4+}$ is unstable, due to inert pair effect, can easily be reduced to stable $\mathrm{Pb}^{2+}$, hence a stronger oxidising agent than $\mathrm{Sn}^{4+}$.
Statement II is false. Due to inert pair effect, the higher oxidation states of group 14 elements becomes less stable for heavier member.
BETA
