Sblock Elements
- sblock Elements 1 Question 21
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- sblock Elements 1 Question 1
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- sblock Elements 1 Question 30
- sblock Elements - Result Question 10
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- sblock Elements 1 Question 14
- sblock Elements 1 Question 17 — JEE PYQ Chapterwise
- sblock Elements 1 Question 15 — JEE PYQ Chapterwise
- sblock Elements 2 Question 16
- sblock Elements 1 Question 18 — JEE PYQ Chapterwise
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- sblock Elements 1 Question 16 — JEE PYQ Chapterwise
- sblock Elements 2 Question 17
- sblock Elements 1 Question 17 — JEE PYQ Chapterwise
- sblock Elements 2 Question 19 — JEE PYQ Chapterwise
- sblock Elements 1 Question 18 — JEE PYQ Chapterwise
- sblock Elements 2 Question 20 — JEE PYQ Chapterwise
- sblock Elements 2 Question 19 — JEE PYQ Chapterwise
- sblock Elements 2 Question 20 — JEE PYQ Chapterwise
- sblock Elements 2 Question 22
- sblock Elements 2 Question 23
- sblock Elements - Result Question 27
- sblock Elements - Result Question 28
- sblock Elements - Result Question 29
- sblock Elements - Result Question 30
- sblock Elements 1 Question 15 — JEE PYQ Chapterwise
- sblock Elements - Result Question 31
- sblock Elements - Result Question 32
- sblock Elements 1 Question 16 — JEE PYQ Chapterwise
- sblock Elements - Result Question 33
- sblock Elements - Result Question 34
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- sblock Elements 1 Question 35
- sblock Elements - Result Question 67
- sblock Elements - Result Question 68
- sblock Elements - Result Question 69
- sblock Elements - Result Question 70
- sblock Elements - Result Question 71
- sblock Elements - Result Question 72
- sblock Elements 2 Question 1 — JEE PYQ Chapterwise
- sblock Elements 2 Question 2
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- sblock Elements 2 Question 1 — JEE PYQ Chapterwise
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- sblock Elements 2 Question 18
sblock Elements 1 Question 30
30. The species that do not contain peroxide ions, is
$(1992,1 \mathrm{M})$
(a) $\mathrm{PbO}_2$
(b) $\mathrm{H}_2 \mathrm{O}_2$
(c) $\mathrm{SrO}_2$
(d) $\mathrm{BaO}_2$
Show Answer
Answer:
Correct Answer: 30. (a)
Solution: In $\mathrm{PbO}_2, \mathrm{~Pb}$ is in +4 oxidation state and oxygen is in -2 oxidation state. In all other case, peroxide ion $\left(\mathrm{O}_2^{2-}\right)$ is present.





