Solid State - Result Question 36
36. The number of hexagonal faces that are present in a truncated octahedron is
(2011)
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Answer:
Correct Answer: 36. $(8)$
Solution:
- The truncated octahedron is the $14$ -faced Archimedean solid, with $14$ total faces : $6$ squares and $8 $ regular hexagons.
The truncated octahedron is formed by removing the six right square pyramids one from each point of a regular octahedron as :
Truncated octahedron unfolded in two-dimension
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