Solutions and Colligative Properties - Result Question 65

Passage

Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life.

One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles.

A solution $M$ is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is $0.9$ .

Given, freezing point depression constant of water

$ \left(K_f^{\text {water }}\right)=1.86 \mathrm{K} \mathrm{kg} \mathrm{mol}^{-1} $

Freezing point depression constant of ethanol

$ \left(K_f^{\text {ethanol }}\right)=2.0 \mathrm{K} \mathrm{kg} \mathrm{mol}^{-1} $

Boiling point elevation constant of water

$ \left(K_b^{\text {water }}\right)=0.52 \mathrm{K} \mathrm{kg} \mathrm{mol}^{-1} $

Boiling point elevation constant of ethanol

$ \left(K_b^{\text {ethanol }}\right)=1.2 \mathrm{K} \mathrm{kg} \mathrm{mol}^{-1} $

Standard freezing point of water $=273 \mathrm{K}$

Standard freezing point of ethanol $=155.7 \mathrm{K}$

Standard boiling point of water $=373 \mathrm{K}$

Standard boiling point of ethanol $=351.5 \mathrm{K}$

Vapour pressure of pure water $=32.8 \mathrm{mm} $ $\mathrm{Hg}$

Vapour pressure of pure ethanol $=40 \mathrm{mm} $ $\mathrm{Hg}$

Molecular weight of water $ =18 $ $\mathrm{g} $ $\mathrm{mol}^{-1}$

Molecular weight of ethanol $=46$ $ \mathrm{g}$ $ \mathrm{mol}^{-1}$

In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.

$(2008,3 \times 4 M=12 M)$

36. The vapour pressure of the solution $M$ is

(a) $39.3$ $ mm$ $ Hg$

(b) $36.0$ $ mm $ $Hg$

(c) $29.5 $ $mm $ $Hg$

(d) $28.8 $ $mm $ $Hg$

Show Answer

Answer:

Correct Answer: 36. (a)

Solution:

Vapour pressure $=p\left(H _2 O\right)+p($ ethanol $)$

$ =32.8 \times 0.1+40 \times 0.9 $

$ =3.28+36 $

$ =39.28$ $ mm$