Some Basic Concepts of Chemistry - Result Question 10 — JEE PYQ Chapterwise

10. For the following reaction, the mass of water produced from $445 g$ of $C _{57} H _{110} O _6$ is :

$ 2 C _{57} H _{110} O _6(s)+163 O _2(g) \rightarrow 114 CO _2(g)+110 H _2 O(l) $

(2019 Main, 9 Jan II)

(a) $490 g$

(b) $495 g$

(c) $445 g$

(d) $890 g$

Show Answer

Answer:

Correct Answer: 10. (b)

Solution:

$2 C _{57} H _{110} O _6(s)+163 O _2(g) \longrightarrow 110 H _2 O(l)+114 CO _2(g)$

Molecular mass of $C _{57} H _{110} O _6$ $=2 \times(12 \times 57+1 \times 110+16 \times 6) g=1780 g$

Molecular mass of $110 H _2 O=110(2+16)=1980 g$

$1780 g$ of $C _{57} H _{110} O _6$ produced $=1980 g$ of $H _2 O$.

$ =495 of H _2 O $

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