Some Basic Concepts of Chemistry - Result Question 13 — JEE PYQ Chapterwise

Answer:

Correct Answer: 13. (b)

Solution:

$\underset{1 g}{M _2 CO _3}+2 HCl \longrightarrow 2 M Cl+\underset{\substack{0.01186 \\ \text { mole }}}{H _2 O}+\underset{2}{CO _2}$

Number of moles of $M _2 CO _3$ reacted $=$ Number of moles of $CO _2$ evolved

$ \begin{aligned} & \frac{1}{M}=0.01186 \quad\left[M=\text { molar mass of } M _2 CO _3\right] \\ & M=\frac{1}{0.01186}=84.3 g mol^{-1} \end{aligned} $