Some Basic Concepts of Chemistry - Result Question 15

Answer:

Correct Answer: 15. (a)

Solution:

Oxalic acid dihydrate $\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}: \mathrm{mw}=126$

It is a dibasic acid, hence equivalent weight $=63$

$\begin{aligned} \Rightarrow & \text { Normality } =\frac{6.3}{63} \times \frac{1000}{250}=0.4 \mathrm{~N} \\ \Rightarrow & N_1 V_1 =N_2 V_2 \\ \Rightarrow & 0.1 \times V_1 =0.4 \times 10 \\ \text { Hence, } & V_1 =40 \mathrm{~mL} \end{aligned}$