Some Basic Concepts of Chemistry - Result Question 13 — JEE PYQ Chapterwise

Answer:

Correct Answer: 22. (a)

Solution:

22. Number of atoms $=$ Number of moles $\times$ Avogadro’s number $\left(N_A\right)$

Number of atoms in $24 \mathrm{~g} \mathrm{C}=\frac{24}{12} \times N_A=2 N_A$

Number of atoms in 56 g of $\mathrm{Fe}=\frac{56}{56} N_A=N_A$

Number of atoms in 27 g of $\mathrm{Al}=\frac{27}{27} N_A=N_A$

Number of atoms in 108 g of $\mathrm{Ag}=\frac{108}{108} N_A=N_A$

Hence, 24 g of carbon has the maximum number of atoms.