Some Basic Concepts of Chemistry - Result Question 22

22. The oxidation number of phosphorus in $Ba\left(H _2 PO _2\right) _2$ is

(1988)

(a) +3

(b) +2

(c) +1

(d) -1

Show Answer

Answer:

Correct Answer: 22. (c)

Solution:

In $\mathrm{Ba}\left(\mathrm{H}_2 \mathrm{PO}_2\right)_2$, oxidation number of Ba is +2 . Therefore,

$\begin{aligned} & & \mathrm{H}_2 \mathrm{PO}_2^{-}: 2 \times(+1)+x+2 \times(-2) & =-1 \\ \Rightarrow & & x & =+1 \end{aligned}$

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