Some Basic Concepts of Chemistry - Result Question 40 — JEE PYQ Chapterwise

45. Find the molarity of water. Given: $\rho=1000 \mathrm{~kg} / \mathrm{m}^3$

(2003)

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Answer:

Correct Answer: 45. $\left(55.56 \mathrm{~mol} \mathrm{~L}^{-1}\right)$

Solution:

$\begin{aligned} & \text { 45. Mass of } 1.0 \mathrm{~L} \text { water }=1000 \mathrm{~g} \\ & \Rightarrow \quad \text { Molarity }=\frac{1000}{18}=55.56 \mathrm{~mol} \mathrm{~L}^{-1}\end{aligned}$

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