Some Basic Concepts of Chemistry - Result Question 51

Answer:

Correct Answer: 50. (10.42)

Solution:

50. $93 % H _2 SO _4$ solution weight by volume indicates that there is $93 g H _2 SO _4$ in $100 mL$ of solution.

If we consider $100 mL$ solution, weight of solution $=184 g$

Weight of $H _2 O$ in $100 mL$ solution $=184-93=91 g$

$\Rightarrow$ Molality $=\frac{\text { Moles of solute }}{\text { Weight of solvent }(g)} \times 1000$

$=\frac{93}{98} \times \frac{1000}{91}=10.42$