States of Matter - Result Question 24
According to Graham’s law, at a given temperature the ratio of the rates of diffusion $\dfrac{r _A}{r _B}$ of gases $A$ and $B$ is given by $\dfrac{r _A}{r _B} = \dfrac{\sqrt{M_B}}{\sqrt{M_A}}$ (where, $M$ are molecular weights of gases $A$ and $B$ respectively)
(a) $\left(\dfrac{p _A}{p _B}\right)\left(\dfrac{M _A}{M _B}\right)^{\dfrac{1}{2}}$
(b) $\left(\dfrac{M _A}{M _B}\right)\left(\dfrac{p _A}{p _B}\right)^{\dfrac{1}{2}}$
(c) $\left(\dfrac{p _A}{p _B}\right)\left(\dfrac{M _B}{M _A}\right)^{\dfrac{1}{2}}$
(d) $\left(\dfrac{M _A}{M _B}\right)\left(\dfrac{p _B}{p _A}\right)^{\dfrac{1}{2}}$
$(1998,2 M)$
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Answer:
Correct Answer: 24. (c)
Solution:
Rate of effusion $\propto p_i ; p_i=$ Partial pressure of $i$th component
$ \propto \sqrt{\dfrac{1}{M}} $
BETA
