States of Matter - Result Question 91
91. Calculate the average kinetic energy, in joule per molecule in 8.0 g of methane at $27^{\circ} \mathrm{C}$.
$(1982,2 M)$
Show Answer
Answer:
Correct Answer: 91. $\left(6.2 \times 10^{-21} \mathrm{~J} /\right.$ molecule $)$
Solution:
$\begin{aligned} \mathrm{KE} & =\dfrac{3}{2} k_B T: k_B=\text { Boltzmann’s constant } \\ & =\dfrac{3}{2} \times 1.38 \times 10^{-23} \times 300 \mathrm{~J}=6.21 \times 10^{-21} \mathrm{~J} / \text { molecule }\end{aligned}$
BETA
