States of Matter - Result Question 96

96. Calculate the density of $NH _3$ at $30^{\circ} C$ and $5 atm$ pressure.

(1978,2 M)

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Answer:

Correct Answer: 96. $(3.42 {~gL}^{-1})$

Solution:

The ideal gas equation :

$ \begin{aligned} p V & =n R T=\frac{w}{M} R T \\ \Rightarrow \quad p M & =\frac{w}{V} R T=d R T \text { where, ’ } d \text { ’ is density. } \\ \Rightarrow \quad d & =\frac{p M}{R T}=\frac{5 \times 17}{0.082 \times 303}=3.42 g L^{-1} \end{aligned} $