Thermodynamics and Thermochemistry - Result Question 61

Fill in the Blanks

61. The total energy of one mole of an ideal monatomic gas at $27^{\circ} C$ is _______ cal.

(1984,1 M)

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Answer:

Correct Answer: 61. $(900)$

Solution:

$900$ $ cal: E=\frac{3}{2} R T=\frac{3}{2} \times 2 \times 300$ $ cal$



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