Circle Ques 45
- If one of the diameters of the circle $x^{2}+y^{2}-2 x-6 y+6=0$ is a chord to the circle with centre $(1,3)$, then the radius of the circle is $\quad(2004,1 M)$
(a) $\sqrt{3}$
(b) $\sqrt{2}$
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Answer:
Correct Answer: 45.(c)
Solution:
- Here, radius of smaller circle, $A C=\sqrt{1^{2}+3^{2}-6}= \sqrt{10-6}= \sqrt{4}=2$
Clearly, from the figure the radius of the bigger circle
$ \begin{alignedat} & r^{2}=2^{2}+\left[(2-1)^{2}+(3-1)^{2}\right] \\ & r^{2}=9 \quad \Rightarrow \quad r=3 \end{aligned} $
BETA
