Functions Ques 62

  1. Which of the following functions is periodic? $(1983,1 M)$

(a) $f(x)=x-[x]$, where $[x]$ denotes the greatest integer less than or equal to the real number $x$

(b) $f(x)=\sin (1 / x)$ for $x \neq 0, f(0)=0$

(c) $f(x)=x \cos x$

(d) None of the above

Objective Question II

(One or more than one correct option)

Show Answer

Answer:

Correct Answer: 62.(c)

Solution:

Formula:

Properties Of Periodic Function:

  1. We have, $f(x)=\frac{x}{1+x^{2}}$

$$ \therefore \quad f \frac{1}{x}=\frac{\frac{1}{x}}{1+\frac{1}{x^{2}}}=\frac{x}{1+x^{2}}=f(x) $$

$\therefore \quad f\left(\frac{1}{2}\right)=f(2)$ or $f\left(\frac{1}{3}\right)=f(3)$ and so on.

So, $f(x)$ is a many-one function.

Again, let $\quad y=f(x) \Rightarrow y=\frac{x}{1+x^{2}}$

$\Rightarrow \quad y+x^{2} y=x \Rightarrow y x^{2}-x+y=0$

As, $\quad x \in \mathbb{R}$

$\therefore \quad(-1)^{2}-4(y)(y) \geq 0$

$\Rightarrow \quad 1-4 y^{2} \geq 0$

$\Rightarrow \quad y \in \left[-\frac{1}{2}, \frac{1}{2}\right]$

$\therefore$ Range $=$ Codomain $=\left[-\frac{1}{2}, \frac{1}{2}\right]$

So, $f(x)$ is surjective.

Hence, $f(x)$ is surjective but not injective.



Table of Contents

sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें