Hyperbola Ques 34

If $x=9$ is the chord of contact of the hyperbola $x^{2}-y^{2}=9$, then the equation of the corresponding pair of tangents is

$(1999,2 M)$

(a) $9 x^{2}-8 y^{2}+18 x-9=0$

(b) $9 x^{2}-8 y^{2}-18 x+9=0$

(c) $9 x^{2}-8 y^{2}-18 x-9=0$

(d) $9 x^{2}-8 y^{2}+18 x+9=0$

Show Answer

Answer:

Correct Answer: 34.(b)

Solution:

  1. Let $(h, k)$ be a point whose chord of contact with respect to hyperbola $x^{2}-y^{2}=9$ is $x=9$.

We know that, chord of contact of $(h, k)$ with respect to hyperbola $x^{2}-y^{2}=9$ is $T=0$.

$\Rightarrow h \cdot x+k(-y)-9=0$

$\therefore \quad h x-k y-9=0$

But it is the equation of the line $x=9$.

This is possible when $h=1, k=0$ (by comparing both equations).

Again equation of pair of tangents is

$ \begin{array}{lc} & T^{2}=S S _1 \\ \Rightarrow & (x-9)^{2}=\left(x^{2}-y^{2}-9\right)\left(1^{2}-0^{2}-9\right) \\ \Rightarrow & x^{2}-18 x+81=\left(x^{2}-y^{2}-9\right)(-8) \\ \Rightarrow & x^{2}-18 x+81=-8 x^{2}+8 y^{2}+72 \\ \Rightarrow & 9 x^{2}-8 y^{2}-18 x+9=0 \end{array} $



Table of Contents

sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें