Inverse Circular Functions Ques 16
- The principal value of $\sin ^{-1} \sin \frac{2 \pi}{3}$ is
(1986, 2M)
(a) $-\frac{2 \pi}{3}$
(b) $\frac{2 \pi}{3}$
(c) $\frac{\pi}{3}$
(d) $\frac{5 \pi}{3}$
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Answer:
Correct Answer: 16.(c)
Solution:
Formula:
Domains and Range of Inverse Trigonometric:
- $\sin ^{-1} (\sin \frac{2 \pi}{3})=\sin ^{-1} [\sin \pi-\frac{\pi}{3}]$
$ =\sin ^{-1} (\sin \frac{\pi}{3})=\frac{\pi}{3} $