(1990, 2M)
Correct Answer: 16.$(1)$
Solution: Given, $\quad f(x)=|x-2|$
$\therefore \quad g(x)=f[f(x)]=| x-2|-2|$
When, $ x>2 $
$g(x)=|(x-2)-2|=|x-4|=x-4$
$\therefore \quad g(x)=1$ when $x>2$
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