Permutations And Combinations Ques 59

  1. Number of divisors of the form $(4 n+2), n \geq 0$ of the integer 240 is

(1998, 2M)

4

8

10

3

Show Answer

Answer:

Correct Answer: 59.(a)

Solution:

Formula:

Combinations of identical objects:

  1. Since, $240=2^{4} \cdot 3 \cdot 5$

$\therefore$ Total number of divisors $=(4+1)(2)(2)=20$

Out of these 2, 6, 10, and 30 are of the form $4n+2$.



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