Probability Ques 101

Passage IV

There are $n$ urns each containing $(n+1)$ balls such that the ith urn contains ‘i’white balls and $(n+1-i)$ red balls. Let $u _i$ be the event of selecting ith urn, $i=1,2,3, \ldots, n$ and $W$ denotes the event of getting a white balls.

$(2006,5$ M)

If $n$ is even and $E$ denotes the event of choosing even numbered urn $[P\left(u _i\right)=\frac{1}{n}]$, then the value of $P(W / E)$ is

(a) $\frac{n+2}{2 n+1}$

(b) $\frac{n+2}{2(n+1)}$

(c) $\frac{n}{n+1}$

(d) $\frac{1}{n+1}$

Show Answer

Answer:

Correct Answer: 101.(b)

Solution:

Formula:

Conditional probability:

  1. $P (\frac{W}{E})=\frac{2+4+6+\ldots}{\frac{n(n+1)}{2}}=\frac{n+2}{2(n+1)}$


Table of Contents