Probability Ques 7

  1. Three identical dice are rolled. The probability that the same number will appear on each of them, is

(1984, 2M)

(a) $\frac{1}{6}$

(b) $\frac{1}{36}$

(c) $\frac{1}{18}$

(d) $\frac{3}{28}$

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Answer:

Correct Answer: 7.(b)

Solution: (b) Since, three dice are rolled.

$\therefore \quad$ Total number of cases $S=6 \times 6 \times 6=216$

and the same number appear on each of them $={ }^6 C_1=6$

$\therefore \quad $ Required probability $=\frac{6}{216}=\frac{1}{36}$



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