(a) $H_1>H_2>H_3>\ldots$
(b) $H_1<H_2<H_3<\ldots$
(c) $H_1>H_3>H_6>\ldots$ and $H_2<H_4<H_6<\ldots$
(d) $H_1<H_3<H_6<\ldots$ and $H_2>H_4>H_6>\ldots$
Correct Answer: 15.(b)
Solution: (b) As above, $A_1>H_2>H_1, A_2>H_3>H_2$
$\therefore \quad H_1<H_2<H_3<\ldots$
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