Correct Answer: (False)
Solution: 28. Since, $\frac{\log _a x+\frac{1}{\log _a x}}{2}>1$, using AM $>$ GM
Here, equality holds only when $x=a$ which is not possible.
So, $\log _a x+\log _x a$ is greater than $2$ .
Hence, it is a false statement.
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