Straight Line And Pair Of Straight Lines Ques 3

Solution:

3. Let the equation of required line having intercepts $a$ and $b$ with the axes is

Now, according to given information,

$P$ is the mid-point of $A B$

$\therefore \quad P=\frac{a}{2}, \frac{b}{2}=(-3,4)$

[given]

$$ \Rightarrow \quad(a, b)=(-6,8) $$

On putting the value of $a$ and $b$ in Eq. (i), we get

$$ \begin{aligned} \frac{x}{-6}+\frac{y}{8} & =1 \Rightarrow 8 x-6 y=-48 \\ \Rightarrow \quad 4 x-3 y+24 & =0 \end{aligned} $$