Theory Of Equations Ques 67
- If both the roots of the quadratic equation $x^{2}-m x+4=0$ are real and distinct and they lie in the interval $[1,5]$ then $m$ lies in the interval
(2019 Main, 9 Jan II)
(a) $(4,5)$
(b) $(-5,-4)$
(c) $(5,6)$
(d) $(3,4)$
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Answer:
Correct Answer: 67.(a)
Solution:
Formula:
- According to given information, we have the following graph
Now, the following conditions should satisfy
(i) $D>0 \Rightarrow b^{2}-4 a c>0$
$ \begin{array}{lc} \Rightarrow & m^{2}-4 \times 1 \times 4>0 \\ \Rightarrow & m^{2}-16>0 \\ \Rightarrow & (m-4)(m+4)>0 \\ \Rightarrow & m \in(-\infty,-4) \cup(4, \infty) \end{array} $
(ii) The vertex of the parabola should lie between $x=1$ and $x=5$
$ \therefore \quad-\frac{b}{2 a} \in(1,5) \Rightarrow 1<\frac{m}{2}<5 \Rightarrow m \in(2,10) $
(iii) $f(1)>0 \Rightarrow 1-m+4>0$
$ \Rightarrow m<5 \Rightarrow m \in(-\infty, 5) $
(iv) $f(5)>0 \Rightarrow 25-5 m+4>0 \Rightarrow 5 m<29 \Rightarrow m \in (-\infty, \frac{29}{5})$
From the values of $m$ obtained in (i), (ii), (iii) and (iv), we get $m \in(4,5)$.
BETA
