Current Electricity Ques 51 — JEE PYQ Chapterwise

Answer:

Correct Answer: 51.(d)

Solution:

51. Given circuit is

Above circuit can be viewed as

This is a parallel combination of three cells or in other words, a parallel grouping of three cells with internal resistances.

So, $\quad V _{a b}=E _{eq}=\frac{I _{eq}}{r _{eq}}=\frac{\frac{E _1}{r _1}+\frac{E _2}{r _2}+\frac{E _3}{r _3}}{\frac{1}{r _1}+\frac{1}{r _2}+\frac{1}{r _3}}$

$ =\frac{\frac{2}{2}+\frac{4}{2}+\frac{4}{2}}{\frac{1}{2}+\frac{1}{2}+\frac{1}{2}}=\frac{10}{3} V \approx 3.3 V $