Electrostatics Ques 132
- Two parallel plate capacitors of capacitances $C$ and $2 C$ are connected in parallel and charged to a potential difference $V$. The battery is then disconnected and the region between the plates of capacitor $C$ is completely filled with a material of dielectric constant $K$. The potential difference across the capacitors now becomes….
(1988, 2M)
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Answer:
Correct Answer: 132.$(\frac{3}{K+2})V$
Solution:
Formula:
Distribution of Charges on Connecting Two Charged Capacitors:
- Total charge will remain unchanged.
Hence, $Q=Q^{\prime}$ or $3 C V=(K C+2 C) V^{\prime}$
BETA
