General Physics Ques 48
Question 26
- Planck’s constant has dimensions
$(1985,2 \mathrm{M})$
Analytical & Descriptive Questions
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Answer:
Correct Answer: 48.$\left[\mathrm{ML}^{2} \mathrm{~T}^{-1}\right]$
Solution:
Formula:
- $E=h \nu$
$$ \therefore \quad h=\frac{E}{v} $$
$$ \text { or }[h]=\frac{[E]}{[\nu]}=\frac{\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]}{\left[\mathrm{T}^{-1}\right]}=\left[\mathrm{ML}^{2} \mathrm{~T}^{-1}\right] $$
BETA
