General Physics Ques 6
- The dimensions of $\frac{1}{2} \varepsilon_0 E^2$ ( $\varepsilon_0$ : permittivity of free space; $E$ : electric field) is
(2000, 2M)
(a) $\left[\mathrm{MLT}^{-1}\right]$
(b) $\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$
(c) $\left[\mathrm{MLT}^{-2}\right]$
(d) $\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
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Answer:
Correct Answer: 6.( None of the four choices )
Solution:
- (None of the four choices) $\frac{1}{2} \varepsilon_0 E^2$ is the expression of energy density (Energy per unit volume)
$ \left[\frac{1}{2} \varepsilon_0 E^2\right]=\left[\frac{\mathrm{ML}^2 \mathrm{~T}^{-2}}{\mathrm{~L}^3}\right]=\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right] $
BETA
