General Physics Ques 7
- In the formula $X=3 Y Z^2, X$ and $Z$ have dimensions of capacitance and magnetic induction, respectively. What are the dimensions of $Y$ in MKSQ system?
(1995, $2 \mathrm{M}$ )
(a) $\left[\mathrm{M}^{-3} \mathrm{~L}^{-1} \mathrm{~T}^3 \mathrm{Q}^4\right]$
(b) $\left[\mathrm{M}^{-3} \mathrm{~L}^{-2} \mathrm{~T}^4 \mathrm{Q}^4\right]$
(c) $\left[\mathrm{M}^{-2} \mathrm{~L}^{-2} \mathrm{~T}^4 \mathrm{Q}^4\right]$
(d) $\left[\mathrm{M}^{-3} \mathrm{~L}^{-2} \mathrm{~T}^4 \mathrm{Q}\right]$
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Answer:
Correct Answer: 7.( b )
Solution:
$\begin{aligned} {[Y] } & =\left[\frac{X}{Z^2}\right]=\left[\frac{\text { Capacitance }}{(\text { Magnetic induction })^2}\right] \\ & =\left[\frac{\mathrm{M}^{-1} \mathrm{~L}^{-2} \mathrm{Q}^2 \mathrm{~T}^2}{\mathrm{M}^2 \mathrm{Q}^{-2} \mathrm{~T}^{-2}}\right]=\left[\mathrm{M}^{-3} \mathrm{~L}^{-2} \mathrm{~T}^4 \mathrm{Q}^4\right]\end{aligned}$
BETA
