Gravitation Ques 18
- If $g$ is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of an object of mass $m$ raised from the surface of the earth to a height equal to the radius $R$ of the Earth, is
$(1983,1 \mathrm{M})$
(a) $\frac{1}{2} m g R$
(b) $2 m g R$
(c) $m g R$
(d) $\frac{1}{4} m g R$
Show Answer
Answer:
Correct Answer: 18.(a)
Solution:
Formula:
Variation Of Acceleration Due To Gravity :
- $\Delta U=\frac{m g h}{1+h / R}$
Given, $h=R$
$$ \Delta U=\frac{m g R}{1+R / R}=\frac{1}{2} m g R $$
BETA
