Heat And Thermodynamics Ques 120
The volume $V$ versus temperature $T$ graphs for a certain amount of a perfect gas at two pressures $p_1$ and $p_2$ are as shown in figure. It follows from the graphs that $p_1$ is greater than $p_2.(1982,2 M)$
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Solution:
Formula:
$$ pV=nRT $$
$$ \therefore \quad V=\left(\frac{n R}{p}\right) T $$
Comparing this with $y=m x, V-T$ graph is a straight line passing through origin with slope $=\frac{n R}{N_A}$
$$ \begin{aligned} & \text { or } \quad \text { slope } \propto \frac{1}{p} \quad (\text { slope })_1 > (\text { slope })_2 \\ & \therefore \quad p _1<p _2 \\ \end{aligned} $$
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