Heat And Thermodynamics Ques 143

  1. A monoatomic ideal gas, initially at temperature $T _1$, is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature $T _2$ by releasing the piston suddenly. If $L _1$ and $L _2$ are the lengths of the gas column before and after expansion respectively, then $T _1 / T _2$ is given by

(2000, 2M)

(a) $\left(L _1 / L _2\right)^{2 / 3}$

(b) $\left(L _1 / L _2\right)$

(c) $L _2 / L _1$

(d) $\left(L _2 / L _1\right)^{2 / 3}$

Show Answer

Answer:

Correct Answer: 143.(d)

Solution:

Formula:

Adiabatic process :

  1. During adiabatic expansion, we know

$$ T V^{\gamma-1}=\text { constant } \text { or } T _1 V _1^{\gamma-1}=T _2 V _2^{\gamma-1} $$

For a monoatomic gas, $\gamma=\frac{5}{3}$

$$ \begin{aligned} \therefore \quad \frac{T _1}{T _2}=\left(\frac{V _2}{V _1}\right)^{\gamma-1} & =\left(\frac{A L _2}{A L _1}\right)^{(5 / 3)-1} \\ (A & =\text { Area of cross-section of piston }) \\ & =\left(\frac{L _2}{L _1}\right)^{2 / 3} \end{aligned} $$



Table of Contents

sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें