Heat And Thermodynamics Ques 43
- Steel wire of length $L$ at $40^{\circ} C$ is suspended from the ceiling and then a mass $m$ is hung from its free end. The wire is cooled down from $40^{\circ} C$ to $30^{\circ} C$ to regain its original length $L$. The coefficient of linear thermal expansion of the steel is $10^{-5}{ }^{\circ} C$, Young’s modulus of steel is $10^{11} N / m^{2}$ and radius of the wire is $1 mm$. Assume that $L>$ diameter of the wire. Then the value of $m$ in $kg$ is nearly.
(2011)
Show Answer
Answer:
Correct Answer: 43.3
Solution:
Formula:
Calorimetry, Thermal Expansion, Types Of Thermometers :(/important-formula/physics/heat_and_thermodynamics)
- $\Delta l _1=\frac{F L}{A Y}=\frac{m g L}{\pi r^{2} Y}=$ Increase in length
$$ $\Delta l = L \alpha \Delta \theta=\text { Decrease in length. }$ $$
To regain its original length, $\Delta l_1 = \Delta l_2$
$\therefore \quad \frac{m g L}{\pi r^{2} Y}=L \alpha \Delta \theta \quad \Rightarrow \quad \therefore \quad m=\left(\frac{r^{2} Y \alpha \Delta \theta}{g}\right)$
Substituting the values we get, $m \simeq 3 kg$
$\therefore$ Answer is 3 .
BETA
