Kinematics Ques 30
- A particle starts from rest. Its acceleration (a) versus time ( $t$ ) is as shown in the figure. The maximum speed of the particle will be
(2004, 2M)
(a) $110 m / s$
(b) $55 m / s$
(c) $550 m / s$
(d) $660 m / s$
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Answer:
Correct Answer: 30.(b)
Solution:
Formula:
- Area under acceleration-time graph gives the change in velocity.
Hence, $\quad v _{\max }=1 / 2 \times 10 \times 11=55 m / s$
BETA
