Laws Of Motion Ques 50 — JEE PYQ Chapterwise

  1. A simple pendulum with a bob of mass $m$ swings with an angular amplitude of $40^{\circ}$. When its angular displacement is $20^{\circ}$, the tension in the string is greater than $m g \cos 20^{\circ}$.

$(1984,2 \mathrm{M})$

Show Answer

Answer:

Correct Answer: 50.$\mathrm{T}$

Solution:

Formula:

Centripetal Force:

  1. $T-m g \cos 20^{\circ}=\frac{m v^{2}}{R}$ or $T=m g \cos 20^{\circ}+\frac{m v^{2}}{R}$
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