Magnetics Ques 111
Assertion and Reason
Mark your answer as
(a) If Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
(b) If Statement I is true, Statement II is true; Statement II is not a correct explanation for Statement I
(c) If Statement I is true; Statement II is false
(d) If Statement I is false; Statement II is true
- Statement I The sensitivity of a moving coil galvanometer is increased by reducing the resistance of the coil.
Soft iron has a high magnetic permeability and can be easily magnetised and demagnetised.
(2008, 3M)
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Answer:
Correct Answer: 111.(c)
Solution:
Formula:
Magnetic Force Acting On A Current Carrying Wire:
- Key Idea: Net force experienced by two wires separated by same distance is attractive, if current flow in them in same direction. However, this force is repulsive in nature, if current in them flows in opposite direction.
Force on a wire $1$ in which current $I_1$ is flowing due to another wire $2$ which are separated by a distance $r$ is given as
or
$ \begin{aligned} & \mathbf{F}=I _1\left(l \times \mathbf{B} _2\right) \\ & F=\frac{\mu _0 I _1 I _2}{2 \pi r} \cdot l \sin \theta \quad [\because \mathbf{B} _1=\frac{\mu _0 I _1}{2 \pi r}] \end{aligned} $
Thus, the given square loop can be represented as shown below
$ \begin{aligned} F _{A B} & =\frac{\mu _0 I _1}{2 \pi a} \cdot I _2 \cdot \frac{a}{2}(\text { away from wire } P Q) \\ F _{B C} & =F _{A D}=0 \quad \left[\because \theta=0^{\circ}\right] \\ F _{C D} & =\frac{\mu _0 I _1}{2 \pi(2 a)} \cdot I _2 \cdot a \\ & \left.=\frac{\mu _0 I _1}{4 \pi a} \cdot I _2 a \text { (towards the wire } P Q\right) \\ \therefore \quad F _{\text {net }} & =F _{A B}-F _{C D} \\ & =\frac{\mu _0 I _1 I _2}{2 \pi}-\frac{\mu _0 I _1 I _2}{4 \pi} \quad \text { (away from wire) } \\ & =\frac{\mu _0 I _1 I _2}{4 \pi} \quad \text { (repulsive in nature) } \end{aligned} $
BETA
