Magnetics Ques 33
- A proton and an alpha particle, after being accelerated through same potential difference, enter uniform magnetic field, the direction of which is perpendicular to their velocities. Find the ratio of radii of the circular paths of the two particles.
(2004, 2M)
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Answer:
Correct Answer: 33.$(\frac{1}{\sqrt{2}})$
Solution:
Formula:
Magnetic Force Acting On A Moving Point Charge:
- $r=\frac{\sqrt{2 q V m}}{B q}$ or $r \propto \sqrt{\frac{m}{q}}$
$ \frac{r _P}{r _{\alpha}}=\sqrt{\frac{m _P}{m _{\alpha}}} \sqrt{\frac{q _{\alpha}}{q _P}}=\sqrt{\frac{1}{4}} \sqrt{\frac{2}{1}}=\frac{1}{\sqrt{2}} $
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