Modern Physics Ques 11
- If the anti-neutrino had a mass of $3 \mathrm{eV} / c^2$ (where $c$ is the speed of light) instead of zero mass, what should be the range of the kinetic energy $K$, of the electron?
(a) $0 \leq K \leq 0.8 \times 10^6 \mathrm{eV}$
(b) $3.0 \mathrm{eV} \leq K \leq 0.8 \times 10^6 \mathrm{eV}$
(c) $3.0 \mathrm{eV} \leq K<0.8 \times 10^6 \mathrm{eV}$
(d) $0 \leq K<0.8 \times 10^6 \mathrm{eV}$
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Answer:
Correct Answer: 11.( d )
Solution:
- Maximum kinetic energy of anti-neutrino is nearly $\left(0.8 \times 10^6\right) \mathrm{eV}$.
BETA
