Modern Physics Ques 117
- Masses of two isobars ${ } _{29} Cu^{64} and _{30} Zn^{64}$ are $63.9298 u$ and $63.9292 u$ respectively. It can be concluded from these data that
(1997C, 1M)
(a) both the isobars are stable
(b) $Zn^{64}$ is radioactive, decaying to $Cu^{64}$ through $\beta$-decay
(c) $Cu^{64}$ is radioactive, decaying to $Zn^{64}$ through $\gamma$-decay
(d) $Cu^{64}$ is radioactive, decaying to $Zn^{64}$ through $\beta$-decay
Show Answer
Solution:
Formula:
- In beta decay, atomic number increases by 1 whereas the mass number remains the same.
Therefore, following equation can be possible
$$ { } _{29}^{64} Cu \rightarrow{ } _{30}^{64} Zn+{ } _{-1} e^{0} $$
BETA
