Modern Physics Ques 120
- The decay constant of a radioactive sample is $\lambda$. The half-life and mean-life of the sample are respectively given by
$(1989,2 M)$
(a) $1 / \lambda$ and $(\ln 2) / \lambda$
(b) $(\ln 2) / \lambda$ and $1 / \lambda$
(c) $\lambda(\ln 2)$ and $1 / \lambda$
(d) $\lambda /(\ln 2)$ and $1 / \lambda$
Show Answer
Answer:
Correct Answer: 120.(b)
Solution:
Formula:
- As we know, $T _{y 2}=\frac{\ln 2}{\lambda}$ and $\tau=\frac{1}{\lambda}$.
BETA
