Modern Physics Ques 132
- In the uranium radioactive series, the initial nucleus is ${ } _{92}^{238} U$ and the final nucleus is ${ } _{82}^{206} Pb$. When the uranium nucleus decays to lead, the number of $\alpha$-particles emitted is …… and the number of $\beta$-particles emitted is …..
(1985, 2M)
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Answer:
Correct Answer: 132.$(8,6)$
Solution:
Formula:
- Number of $\alpha$-particles emitted, $n _1=\frac{238-206}{4}=8$
and number of $\beta$-particles emitted are say $n _2$, then
$\therefore \quad 92-8 \times 2+n _2 =82 $
$n _2 =6$
BETA
